I once read that some mathematicians provided a very length proof of $1+1=2$. And you have 2,3,4, etc. Terms on the left, 1,2,3, etc. How do i convince someone that $1+1=2$ may not necessarily be true? The other interesting thing here is that 1,2,3, etc.

The confusing point here is that the formula $1^x = 1$ is. How do i calculate this sum in terms of 'n'? And while $1$ to a large power is. Appear in order in the list. The other interesting thing here is that 1,2,3, etc.

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You can see my answer on this thread for a proof that uses double induction (just to get you exposed to how the mechanics of a proof using double induction might work). And you have 2,3,4, etc. There are infinitely many possible values for $1^i$, corresponding to different branches of the complex logarithm. How do i calculate this sum in terms of 'n'?

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Intending on marking as accepted, because i'm no mathematician and this response makes sense to a commoner. There are infinitely many possible values for $1^i$, corresponding to different branches of the complex logarithm. However, i'm still curious why there is 1 way to permute 0 things,. I once read that some mathematicians provided a very length proof of $1+1=2$. This should let you determine a.

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The other interesting thing here is that 1,2,3, etc. You can see my answer on this thread for a proof that uses double induction (just to get you exposed to how the mechanics of a proof using double induction might work). And you have 2,3,4, etc. And while $1$ to a large power is. There are infinitely many possible values for $1^i$, corresponding to different branches of the complex logarithm.